You can put this solution on YOUR website! A rectangular garden has perimeter 66ft and area 216ft squared. Find the dimensions of the garden.
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Let L = length
and W = width
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Since we have two unknowns, we'll need two equations:
For any rectangle:
2(L+W) = perimeter
2(L+W) = 66
L+W = 33 (equation 1)
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For any rectangle:
LW = area
LW = 216 (equation 2)
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Solve equation 1 for L:
L+W = 33
L = 33-W
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Substitute the above into equation 2 and solve for W:
LW = 216
(33-W)W = 216
33W-W^2 = 216
0 = W^2-33W+216
0 = (W-24)(W-9)
W={24,9}
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Dimensions:
length is 24 feet
width is 9 feet
