You can put this solution on YOUR website! Find two consecutive odd integers that the sum of whose squares is 130.
.
Let x = first consecutive odd integer
x+2 = second consecutive odd integer
.
x^2 +(x+2)^2 = 130
x^2 +(x^2+4x+4) = 130
2x^2+4x+4 = 130
2x^2+4x-126 = 0
x^2+2x-63 = 0
(x-7)(x-9) = 0
x = (7,9)
.
Solution: 7 and 9