Question 160136: Suppose you invested 10,000 dollars in two stocks and the first stock increased in value by 12% while the second stock decreased in value by 8%. If your total profit was 800 dollars, then how much did you invest in each stock?
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! .12X-.08(10,000-X)=800
.12X-800+.08X=800
.20X=800+800
.20X=1,600
X=1,600/.20
X=8000 AMOUNT INVESTED @ 12%.
10,000-8,000=2,000 INVESTED @ 8%.
PROOF:
.12*8,000-.08*2,000=800
960-160=800
800=800
|
|
|
