SOLUTION: Using the factoring methd, solve for the roots of each quadraic equation. Place equation in standard form before factoring. x^2 + 3 - 40=0 x^2 = 10x - 24 p^2 +15p + 25 = 6p + 5

Algebra ->  Coordinate-system -> SOLUTION: Using the factoring methd, solve for the roots of each quadraic equation. Place equation in standard form before factoring. x^2 + 3 - 40=0 x^2 = 10x - 24 p^2 +15p + 25 = 6p + 5      Log On


   

Question 159991This question is from textbook Beginning Algebra
: Using the factoring methd, solve for the roots of each quadraic equation. Place equation in standard form before factoring.
x^2 + 3 - 40=0
x^2 = 10x - 24
p^2 +15p + 25 = 6p + 5 This question is from textbook Beginning Algebra

Found 2 solutions by Fombitz, checkley77:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+3x+-+40=0
%28x%2B8%29%28x-5%29=0
x=5,-8
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.
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x%5E2+=+10x+-+24
x%5E2-10x%2B24=0
%28x-4%29%28x-6%29=0
x=4,6
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.
.
p%5E2+%2B15p+%2B+25+=+6p+%2B+5
p%5E2+%2B9p+%2B+20+=+0
%28p%2B4%29%28p%2B5%29=0
p=-4,-5

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 3 - 40=0
(x+8)(x-5)=0
x=-8 answer
x-5=0
x=5 answer.
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x^2 = 10x - 24
x^2-10x+24=0
(x-6)(x-4)=0
x-6=0
x=6 answer.
x-4=0
x=4 answer.
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p^2 +15p + 25 = 6p + 5
p^2+15p-6p+25-5=0
p^2+9p+20=0
(p+4)(p+5)=0
p+4=0
p=-4 answer.
p+5=0
p=-5 answer.