SOLUTION: Lois rides her bike to visit a friend. She travels at 10 mi/h. While shes there, it starts to rain. Her friend drives her home in a car traveling at 25 mi/h. It takes lois 1.5h lon
Algebra ->
Expressions-with-variables
-> SOLUTION: Lois rides her bike to visit a friend. She travels at 10 mi/h. While shes there, it starts to rain. Her friend drives her home in a car traveling at 25 mi/h. It takes lois 1.5h lon
Log On
Question 159969: Lois rides her bike to visit a friend. She travels at 10 mi/h. While shes there, it starts to rain. Her friend drives her home in a car traveling at 25 mi/h. It takes lois 1.5h longer to to friends than it does to return home.How many hours did it take lois to ride to her friends house? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Lois rides her bike to visit a friend. She travels at 10 mi/h. While shes there,
it starts to rain. Her friend drives her home in a car traveling at 25 mi/h.
It takes Lois 1.5h longer to go to friend's house than it does to return home.
How many hours did it take Lois to ride to her friends house?
:
Let t = time in hrs for reach friend's house
then
(t-1.5) = time for friend to drive her home
:
Both trips are the same distance, Write a distance equation from this fact:
Dist = speed * time
:
Drive dist = Bike dist
25(t-1.5) = 10t
:
25t - 37.5 = 10t
:
25t - 10t = +37.5
:
15t = 37.5
t =
t = 2.5 hrs to ride to her friends house
:
:
Check solution by finding the distances, should be equal:
10*2.5 = 25 mi
25*(2.5-1.5) = 25 mi
