SOLUTION: hello. i'm on chapter 5 section 4 problem 20.
thanks for helping me
can you work that problem out for me? what confuses me is i had a negative twelve for the square root, and i k
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Quadratic-relations-and-conic-sections
-> SOLUTION: hello. i'm on chapter 5 section 4 problem 20.
thanks for helping me
can you work that problem out for me? what confuses me is i had a negative twelve for the square root, and i k
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Question 159885This question is from textbook algebra 2
: hello. i'm on chapter 5 section 4 problem 20.
thanks for helping me
can you work that problem out for me? what confuses me is i had a negative twelve for the square root, and i know that square roots aren't suppose to be negative so then i multiplied each side by negative one, but then that left the x squared negative, and i don't know how to write that in paranthesis to be correct. I'm afraid i went wrong from there so can u please explain that and the whole problem to me?
0=x2-6x+3 (the first x is supposed to be squared) This question is from textbook algebra 2
You can put this solution on YOUR website! I'm not quite sure of what you are trying to do. Are you trying to solve for x? If not, then what are the exact instructions?
Start with the given equation.
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for x
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Simplify the square root (note: If you need help with simplifying square roots, check out this solver)