SOLUTION: a man at A walks to a neigborhoring town, B, at the rate of 5mph and returns at a alower rate of 4mph. if it took him 3 hours and 9 minutes for the entire trip, how far is town fro
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Question 159793: a man at A walks to a neigborhoring town, B, at the rate of 5mph and returns at a alower rate of 4mph. if it took him 3 hours and 9 minutes for the entire trip, how far is town from A. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
T=D/R
3.15=D/5+D/4
3.15=(4D+5D)/20
3.15=9D/20 CROSS MULTIPLY.
9D=20*3.15
9D=63
D=63/9
D=7 MILES BETWEEN A & B.
PROOF:
3.15=7/5+7/4
3.15=(4*7+5*7)/20
3.15=(28+35)/20
3.15=63/20
3.15=3.15
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