SOLUTION: The fuel for a two-cycle motorboat engine is a mixture of gasoline and oil in the ratio of15 to 1. How many liters of each are in 6.6 L mixture ?
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Question 159788: The fuel for a two-cycle motorboat engine is a mixture of gasoline and oil in the ratio of15 to 1. How many liters of each are in 6.6 L mixture ? Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! The fuel for a two-cycle motorboat engine is a mixture of gasoline and oil in the ratio of 15 to 1. How many liters of each are in 6.6 L mixture ?
"the ratio of 15 to 1" means that for every 15L of gasoline, we add 1L of oil.
So if we have a 16L mixture, we would have 1L of oil and 15L of gas---OK
Now we can set up our ratio:
Let x=amount of oil in the 6.6L mixture
Then 6.6-x=amount of gas
16 is to 1 as 6.6 is to x and this is written in math terms as follows:
16/1=6.6/x multiply each side by x or cross multiply
16x=6.6 divide each side by 16
x=0.412L----amount of oil in the 6.6L mixture
6.6-x=6.6-0.412=6.188L-----amount of gas
CK
6.188/0.412=15/1
15~~~~~~15 roundoff error
Hope this helps--ptaylor
