SOLUTION: The length of a rectangle is 9 inches greater than the width. The area is 36 inches squared. Find the dimensions. Then I have 6 boxes each fo width, length and area. How do I f
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Question 159760: The length of a rectangle is 9 inches greater than the width. The area is 36 inches squared. Find the dimensions. Then I have 6 boxes each fo width, length and area. How do I figure this out? Thank you. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! L=w+9
A=Lw=36"^2
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w(w+9)=36 Substitute w+9 for L.
w^2+9w=36
w^2+9w-36=0
(w+12)(w-3)=0
w=3, L=12
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Ed
