Question 159597This question is from textbook Intermediate Algebra
: Five times the smallest of three consecutive odd integers is ten more than twice the largest. Find the integers. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! 5x=10+2(x+4)
5x=10+2x+8
5x-2x=18
3x=18
x=18/3
x=6 answer for the smallest integer.
Proof:
5*6=10+2(6+4)
30=10+2*10
30=10+20
30=30