SOLUTION: Applications A golfer's tee shot follows a path given by y = 64t - 16t2, where y is the height of the ball (in feet) after t seconds of flight. How long will it take for the ball t

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Question 159583: Applications A golfer's tee shot follows a path given by y = 64t - 16t2, where y is the height of the ball (in feet) after t seconds of flight. How long will it take for the ball to strike the ground?
seconds
I do not understand how to do this can you show me the steps to solve
Answer by KnightOwlTutor(293) About Me  (Show Source):
You can put this solution on YOUR website!
This is a type of quadratic equation commonly used in physics.
In other words it is the shape of a parabola. It reaches a max and comes back down to the point of origin.When the ball hits the ground x=0 there is no distance traveled
therefore the equation becomes 0=64t-16t2
factor the equation 0=4t(16-t)
the only times where this equation is 0 is when t=0 and when t=16
therefore it takes 16 seconds for the ball to reach the ground.
ground distance=0.