SOLUTION: Sally invested $4500.00. Part of it was invested at 7.5% and part of it was 6%. After one year her interest was $303.00. How much was invested at each rate?

Algebra ->  Equations -> SOLUTION: Sally invested $4500.00. Part of it was invested at 7.5% and part of it was 6%. After one year her interest was $303.00. How much was invested at each rate?      Log On


   



Question 159477: Sally invested $4500.00. Part of it was invested at 7.5% and part of it was 6%. After one year her interest was $303.00. How much was invested at each rate?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.075X+.06(4500-X)=303
.075X+270-.06X=303
.015X=303-270
.015X=33
X=33/.015
X=2,200 INVESTED @ 7.5%
4500-2200=2300 INVESTED @ 6%
PROOF:
.075*2200+.06*2300=303
165+138=303
303=303