Question 15943: I need help on this problem:
Three times the greatest of three consucutive intergers exceeds twice the least by 38. Find the intergers. Answer by pwac(253) (Show Source):
You can put this solution on YOUR website! let 1st integer=x
so 2nd =x+1
and 3rd=x+2
so 3 times greatest(x+2)= 2 times least(x)plus 38.This looks like:
3(x+2)=2x+38 Remove bracket by multiplying by the 3
3x+6=2x+38 Subtract 2x from both sides
x+6=38 subtract 6 from both sides
x=32
which is the smallest of the 3 integers you are looking for
Pete
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