SOLUTION: in 1 2/5 hours more time, Janet Wood, riding her bicycle at 14 mph, rode 12 miles farther than Chrissy Snow, who was riding her bicycle at 16 mph. how far did each girl ride their
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-> SOLUTION: in 1 2/5 hours more time, Janet Wood, riding her bicycle at 14 mph, rode 12 miles farther than Chrissy Snow, who was riding her bicycle at 16 mph. how far did each girl ride their
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Question 159300: in 1 2/5 hours more time, Janet Wood, riding her bicycle at 14 mph, rode 12 miles farther than Chrissy Snow, who was riding her bicycle at 16 mph. how far did each girl ride their bicycle? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! 1 2/5 hours more time, Janet Wood, riding her bicycle at 14 mph, rode 12 miles farther than Chrissy Snow, who was riding her bicycle at 16 mph. how far did each girl ride their bicycle?
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We can write the hrs as: 1.4 hrs
:
Let d = dist ridden by C
then
(d+12) = dist ridden by J
:
Write a time equation: Time =
:
J's time - C's time = 1.4 hrs - = 1.4
:
Multiply equation by 112 to get rid of the denominators
112* - 112* = 112 * 1.4
8(d+12) - 7d = 156.8
;
8d + 96 - 7d = 156.8
:
8d - 7d = 156.8 - 96
:
d = 60.8 mi ridden by C, then: 72.8 mi ridden by J
:
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Check solution by finding the times
72.8/14 = 5.2
60.8/16 = 3.8
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differ = 1.4 hrs; confirms our solution