SOLUTION: 1)one of two complementary angles has a measure that is six more than twice the other's. Find teh measure of the larger angle. this is what i have: X= 6+(90-X)+2(90-X) and

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Question 159295: 1)one of two complementary angles has a measure that is six more than twice the
other's. Find teh measure of the larger angle.
this is what i have: X= 6+(90-X)+2(90-X) and i got 42 degrees?
2) the measure of the supplement of an angle is five times that of the angle's complement. Find the measure of the complement.
this is what i have: (180-X)=5(90-X) and my answer is completely wrong
If you could help me i would really appreciate it, thanks
Found 2 solutions by vleith, nerdybill:
Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website!
1) Let one angle be x. The other angle is 2x+6. The two angles together equal 90
so

The larger angle is 2*28 + 6 = 62.
2)Use the same process as problem one for this one.
Let x be the angle. The complement is then (90-x). The Supplement is (180-x)
You are told the supplement is 5 times the complement.
So

The complement is 90-67.5 = 22.5
The supplement is 180 - 67.5 -= 112.5
The

Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website!
1)one of two complementary angles has a measure that is six more than twice the
other's. Find teh measure of the larger angle.
.
Let x = the larger angle
then because they are complementary:
90-x = the smaller angle
.
then from: "one of two complementary angles has a measure that is six more than twice the other's"
x = 2(90-x)+6
x = 180-2x+6
x = 186-2x
3x = 186
x = 62 degrees
2) the measure of the supplement of an angle is five times that of the angle's complement. Find the measure of the complement.
.
Let x = the angle
180-x = the supplement of the angle
.
180-x = 5x
180 = 6x
30 = x (the angle)
.
Supplement of the angle:
180-x = 180-30 = 150 degrees