SOLUTION: angle A is half as large as twice its supplement angle B

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Question 159264This question is from textbook Texas Geometry
: angle A is half as large as twice its supplement angle B This question is from textbook Texas Geometry

Found 2 solutions by nerdybill, t_as87:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
angle A is half as large as twice its supplement abgle B
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This problems expects you to know the definition of "supplement". Two angles are supplement to each other if the sum of the two angles = 180.
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Let A = "angle A"
then
180-A = "angle B"
then from: "angle A is half as large as twice its supplement abgle B"
we get
A = (1/2)(2)(180-A)
A = 180-A
2A = 180
A = 90 degrees (angle A)
.
Angle B then is:
180-A = 180-90 = 90 degrees (angle B)

Answer by t_as87(5) About Me  (Show Source):
You can put this solution on YOUR website!
So we know that supplemental angles have a sum of 180
so A + B = 180
we also know that A = (1/2)* 2B
by simplification, A = B
so A = 90 and B = 90