SOLUTION: Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 159258This question is from textbook Algebra And Trigonometry
: Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have? This question is from textbook Algebra And Trigonometry

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have?
.
Let q = number of quarters
then from "she has twice as many dimes as quarters"
2q = number of dimes
and from "five more nickels than dimes"
2q+5 = number of nickels
.
Since she has a total of $3.00:
.25q + .10(2q) + .05(2q+5) = 3.00
.25q + .20q + .10q + .25 = 3.00
.55q + .25 = 3.00
.55q = 2.75
q = 2.75/.55
q = 5 (number of quarters)
.
number of dimes:
2q = 2(5) = 10 (number of dimes)
.
number of nickels:
2q+5 = 2(5)+5 = 10 + 5 = 15 (number of nickels)