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| Question 159256:  How do you solve: n^2 - 10n = -21  ?
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! How do you solve: n^2 - 10n = -21 ? --------------
 Put it into quadratic form:
 n^2 - 10n + 21 = 0
 One way is to factor it.
 It will factor into (n - a)*(n - b)
 a*b is 21
 a+b is 10
 a and b have the same sign, since their product, a*b, is positive.
 The only (integer) factors that work to make a*b 21 are:
 21*1 and 7*3.
 21 and 1 add up to 22, so that's no good.
 7 and 3 total 10, which is the coefficient of the middle term, so that's the ones we're looking for.
 (n - 3)*(n - 7) = 0
 So n = 3, n = 7
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 You can use the quadratic equation, too.
 
 
 | Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |  | Quadratic equation  (in our case  ) has the following solutons: 
 
  
 For these solutions to exist, the discriminant
  should not be a negative number. 
 First, we need to compute the discriminant
  :  . 
 Discriminant d=16 is greater than zero. That means that there are two solutions:
  . 
 
  
  
 Quadratic expression
  can be factored: 
  Again, the answer is: 7, 3.
Here's your graph:
 
  |  The onsite solver always uses x, so sub n for x.
 
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