SOLUTION: How do you solve: n^2 - 10n = -21 ?

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Question 159256: How do you solve: n^2 - 10n = -21 ?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve: n^2 - 10n = -21 ?
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Put it into quadratic form:
n^2 - 10n + 21 = 0
One way is to factor it.
It will factor into (n - a)*(n - b)
a*b is 21
a+b is 10
a and b have the same sign, since their product, a*b, is positive.
The only (integer) factors that work to make a*b 21 are:
21*1 and 7*3.
21 and 1 add up to 22, so that's no good.
7 and 3 total 10, which is the coefficient of the middle term, so that's the ones we're looking for.
(n - 3)*(n - 7) = 0
So n = 3, n = 7
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You can use the quadratic equation, too.
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-10x%2B21+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-10%29%5E2-4%2A1%2A21=16.

Discriminant d=16 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--10%2B-sqrt%28+16+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-10%29%2Bsqrt%28+16+%29%29%2F2%5C1+=+7
x%5B2%5D+=+%28-%28-10%29-sqrt%28+16+%29%29%2F2%5C1+=+3

Quadratic expression 1x%5E2%2B-10x%2B21 can be factored:
1x%5E2%2B-10x%2B21+=+%28x-7%29%2A%28x-3%29
Again, the answer is: 7, 3. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-10%2Ax%2B21+%29

The onsite solver always uses x, so sub n for x.