SOLUTION: (8^2x)(4^(2x – 1)) = 16

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Question 159168This question is from textbook Elementary and Intermediate Algebra: A Combined Approach
: (8^2x)(4^(2x – 1)) = 16 This question is from textbook Elementary and Intermediate Algebra: A Combined Approach

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assume the problem is:
8%5E%282x%29%2A4%5E%282x-1%29 = 16
log%288%5E%282x%29%29+%2B+log%284%5E%282x-1%29%29 = log(16)
log equiv of exponents
2x%2Alog%288%29+%2B+%282x-1%29%2Alog%284%29 = log(16)
:
Find the logs
.9031(2x) + .6021(2x-1) = 1.2041
:
1.8062x + 1.2042x - .6021 = 1.2041
:
3.01x = 1.2041 + .6021
:
3.01x = 1.8062
x = 1.8062%2F3.01
x = .6
:
:
Check solution on a calc; (8^1.2) * (4^.2) = 16