SOLUTION: Suppose that a certain radioactive substance has a half-life of 20 years. If there are presently 2500 milligrams of the substance, how much, to the nearest milligram, will remain
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-> SOLUTION: Suppose that a certain radioactive substance has a half-life of 20 years. If there are presently 2500 milligrams of the substance, how much, to the nearest milligram, will remain
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You can put this solution on YOUR website! Suppose that a certain radioactive substance has a half-life of 20 years. If there are presently 2500 milligrams of the substance, how much, to the nearest milligram, will remain after 50 years?
:
Using the half-life formula: A = Ao*(2^(-t/h))
Where:
A = final amt
Ao = initial amt (2500 mg)
t = time (50 yrs)
h = half-life of the substance (20 yrs)
:
A = 2500 * 2^(-50/20)
:
A = 2500 * 2^(-5/2)
:
Use a calculator to find 2^(-5/2) value
A = 2500 * .1767767
:
A = 441.94 ~ 442 mg
