SOLUTION: a + b =1 a^-1 + b^-1 = 1 prove a = b and a^-1 = b^-1 I have that a = b / (b-1) b = 1-a plugging in b to a I get a = (1-a)/a set those equal (1-a)

Algebra ->  Geometry-proofs -> SOLUTION: a + b =1 a^-1 + b^-1 = 1 prove a = b and a^-1 = b^-1 I have that a = b / (b-1) b = 1-a plugging in b to a I get a = (1-a)/a set those equal (1-a)      Log On


   



Question 159161: a + b =1 a^-1 + b^-1 = 1 prove a = b and a^-1 = b^-1
I have that
a = b / (b-1)
b = 1-a
plugging in b to a
I get a = (1-a)/a
set those equal
(1-a)/a = b/(b-1)
can't solve any further

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not sure if you have the right equations. If a=b, then this means that a%2Bb=1 becomes a%2Ba=1 ===> 2a=1 which is NOT true for all values of "a". So double check the problem.