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Question 159067: Find two consecutive integers such that three times the first equals twice the second.
Answer by KnightOwlTutor(293) (Show Source):
You can put this solution on YOUR website! Integer 1=X Integer 2= X=1. A consecutive number would be the next one. ie 1,2,3 etc.
3X=2(X+1) Use the distributive property. 3X=2X+2
Subtract 2X from 3X = X=2 therfore the consecutive #'s are 2 and 3. To double check replace integers into the equation: (3)(2)=2(3)
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