SOLUTION: How do i go about figuring out how to write an equation in slope-intercept form that satisfies each given condition and finding the slope when the x-intercept = 3 and the y-interce

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Question 158993: How do i go about figuring out how to write an equation in slope-intercept form that satisfies each given condition and finding the slope when the x-intercept = 3 and the y-intercept = 2 and there is no slope given
Found 2 solutions by checkley77, gonzo:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
The given points are:(3,0) & (0,2)
The slope formula is: m=(y2-y1)/(x2-x1)
m=(2-0)/(0-3)=2/-3=-2/3 is the slope.
Y=mX+b
y=-2x/3+2 is the line equation through (3,0) & (0,2).
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-2x%2F3+%2B2%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -2x/3 +2).

Answer by gonzo(654) About Me  (Show Source):
You can put this solution on YOUR website!
knowing the x-intercept and the y-intercept give you 2 point from which you can calculate the slope.
in your example, y-intercept = 2 means the point is (0,2) since the y-intercept is the y value when x value = 0.
x-intercept = 3 means the point is (3,0) since the x-intercept is the x value when y = 0.
now that you have 2 points, you can calculate the slope.
slope-intercept formula is y = m*x + b where m is the slope and b is the y-intercept.
your 2 data points are (x1,y1), and x2,y2) from which you can calculate the slope by using the following equation
slope+=+%28y2-y2%29%2F%28x2-x1%29
let (x2,y2) = (0,2)
let (x1,y1) = (3,0)
slope = %282-0%29%2F%280-3%29 = 2%2F-3 = -%282%2F3%29
slope-intercept equation now becomes y=-%282%2F3%29%2Ax+%2B+b
now all you have to do is solve for b.
to solve for b, use one of the points that are part of the line.
we'll use (3,0) first.
y+=+-%282%2F3%29%2Ax+%2B+b becomes 0+=+-%282%2F3%29%2A3+%2B+b
this becomes 0+=+-2+%2B+b
solving for b gets
b = 2
full slope-intercept equation then looks like y=-%282%2F3%29%2Ax%2B2
using this formula and substituting for values using the other point of (0,2) gets 2+=+-%282%2F3%29%2A%280%29+%2B+2 which becomes 2 = 2 which is an identity proving the formula is correct.
using this formula and substituting for values using the first point used of (3,0) gets 0+=+-%282%2F3%29%2A3+%2B+2 which becomes 0+=+-2%2Ax+%2B+2 which becomes 0 = 0 which is an identify proving the formula is correct.
the answer is y=-%282%2F3%29%2Ax%2B2