SOLUTION: what is the value of x in this equation 2 raise to the -5 = (1 + 0.23x)raise to -3

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Question 158856: what is the value of x in this equation
2 raise to the -5 = (1 + 0.23x)raise to -3
Answer by ranjithraghuram(4) About Me  (Show Source):
You can put this solution on YOUR website!
2^-5 = (1+0.23x)^-3
1/(2)^5 = 1/(1+0.23x)^3
1/32 = 1/(1+0.23x)^3
Cross multiply the equation
32=(1+0.23x)^3
Cuberoot of 32 is 3.174802
so (1+0.23x) = 3.174802... Subract 1 from both sides
0.23x = 2.174802 Divide by 0.23 on both sides
x= (2.174802)/0.23
x= 9.4556 ~~ 9.5