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| Question 158825:  Could you help with this problem?  It is from a worksheet.
 The excess of an angle over its supplement is 20 degrees.  Find the angle.
 I tried  x/180-x = 20  It doesn' come out even.
 Found 2 solutions by  Electrified_Levi, checkley77:
 Answer by Electrified_Levi(103)
      (Show Source): 
You can put this solution on YOUR website! Hi, Hope I can help, .
 Could you help with this problem? It is from a worksheet.
 The excess of an angle over its supplement is 20 degrees. Find the angle.
 I tried x/180-x = 20 It doesn' come out even.
 .
 Supplementary angles always add up to 180 degrees
 .
 first we have to find the variables of the angles
 .
 The excess of an angle over its supplement is 20 degrees (excess means exceeding, or more than)
 .
 One angles would be "x"
 .
 The other angle ( The excess of an angle over its supplement is 20 degrees) is "x+20" ( This angle is 20 degrees more than the first angle "x")
 .
 One angle =
  degrees .
 The second angle =
  degrees .
 Now just add the angles together (supplementary angles add up to 180 degrees
 .
 The equation would be
  , now just solve for "x" .
 
  =  , add like terms .
 
  =  =  .
 Move "20" to the right side
 .
 
  =  =  .
 To solve for "x" we will divide each side by "2"
 .
 
  =  =  .
 x =
  .
 We can check by replacing "x" with "80" in our equation
 .
 
  =  =  =  =  (True) .
 x =
  .
 Our two angle measurements were: (Replace "x" with "80" )
 .
 One angle =
  degrees,  degrees .
 The second angle =
  degrees,  degrees,  degrees .
 The two angles add up to 180 degrees,
  =  (True) .
 The two angles are:
 .
 1.
  degrees 2.
  degrees, (the first angle's supplement) .
 Hope I helped, Levi
Answer by checkley77(12844)
      (Show Source): 
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