Question 158698: 1)number problems: the sum of three positive numbers is 33. the second number is 3 greater than the first and the third is 4 times the first. find the three numbers.
2) number problem: the sum of three positive numbers is 24. the second number is 4 greater than the first and the the third is 3 times the first. find the three numbers.
Answer by anjamini(3)   (Show Source):
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question 1:
let the first number = x
so, the second number = x + 3
and the third number = 4x
sum of all the numbers = 33
so, x +(x+3) + 4x = 33
or, x+ x+ 3 + 4x = 33
or, 6x + 3 = 33
or, 6x = 33-3
6x = 30
so, x = 30/6
so, x= 5
so, x+ 3
= 5+3 = 8
4x = 4*5 = 20
check :
replacing x by 5, we get :
5 + 8 + 20 = 33
so, the three numbers are : 5, 8 and 20
question 2:
let the first number = n
so, the second number is n +4
the third number is 3n
the sum of the numbers is 24
so, n + (n+4) + 3n
= n + n + 4 + 3n
= 5n + 4
so, 5n +4 = 24
or, 5n = 24 - 4
or, 5n = 20
or, n = 20/5
0r, n = 4
so, n+4 = 4 + 4 = 8
3n = 3 * 4 = 12
check :
replacing n by 4, we get :
4+ (4+4) +(3*4)
= 4 + 8 + 12
= 24
so, the three numbers are 4, 8 and 12
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