SOLUTION: on average, a canada goose can fly 10 mph faster than a great blue heron. find their flying speeds if a goose can fly 120 miles in the same time it takes a heron to fly 80 miles

Algebra ->  Human-and-algebraic-language -> SOLUTION: on average, a canada goose can fly 10 mph faster than a great blue heron. find their flying speeds if a goose can fly 120 miles in the same time it takes a heron to fly 80 miles      Log On


   

Question 158692This question is from textbook beginning and intermidiate algebra
: on average, a canada goose can fly 10 mph faster than a great blue heron. find their flying speeds if a goose can fly 120 miles in the same time it takes a heron to fly 80 miles This question is from textbook beginning and intermidiate algebra

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
Remember: Speed=distance%2Ftime ---> S=D%2Ft-------------> working eqn
Goose=GO=10%28mph%29%2Bx Speed of goose
BlueHeron=BH=x%28mph%29 Speed of Blue Heron
In working eqn we get,
t%5BGO%5D=D%5BGO%5D%2FS%5BGO%5D; t%5BBH%5D=D%5BBH%5D%2FS%5BBH%5D
Since Goose and Blue Heron travel at the same time---> it cancels out, it's constant. And equating the 2 time equations:
D%5BGO%5D%2FS%5BGO%5D=D%5BBH%5D%2FS%5BBH%5D
120%2F%2810%2Bx%29=80%2Fx, cross multiply
80%2810%2Bx%29=120x
800%2B80x=120x
800=120x-80x
800=40x -----> cross%28800%2920%2Fcross%2840%29=cross%2840%29x%2Fcross%2840%29
x=20mph ------------------------------------> Speed of Blue Heron
10%2Bx=10%2B20=30mph ---------------------------> speed of Goose
To check, going back working eqn, they should travel at the same time with their speed at their distance:
t%5BBH%5D=80cross%28miles%29%2F%2820cross%28miles%29%2Fhr%29=4hrs
t%5BGO%5D=120cross%28miles%29%2F%2830cross%28miels%29%2Fhr%29=4hrs
:t%5BBH%5D=t%5BGO%5D
Thank you,
Jojo