SOLUTION: how many gallons of a 20% acid solution must be mixed with 6 gallons of a 30% acid solution to make a 22% acid solution?

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Question 158688: how many gallons of a 20% acid solution must be mixed with 6 gallons of a 30% acid solution to make a 22% acid solution?
Answer by KnightOwlTutor(293) About Me  (Show Source):
You can put this solution on YOUR website!
X= the number of gallons of a 20% acid solution. The equation for the above problem is .20X + (.30x6)=.22(X + 6) I converted the % to decimals. ie 20%=.2 just divide by 100. therefore .20X + 1.8 = .22X + 1.32 Subtract .20x from .22 and you get .02X Subtract 1.32 from 1.8 and get 0.48. Now you can solve for X 0.48=.02X X=24 gallons. To check the result plug in X and see if you get the same answer on both sides!