Question 158512: There are three consecutive even intergers. If twice the first integer added to the second is 268,262,find al three integers.
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 2X+X+2=268,262
3X=268,262-2
3X=268,260
X=268,260/3
X=89,420 FOR THE SMALLEST INTEGER.
89,420+2=89,422 FOR THE SECOND INTEGER.
89,420=4=89,424 FOR THE THIRD INTEGER.
2*89,420+89,422=268,262
178,840+89,422=268,262
268,262=268,262
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