SOLUTION: (3y^8)^4 / (2zy^2) I started out with (3y^32) / (2zy^2) not sure where to go from here

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: (3y^8)^4 / (2zy^2) I started out with (3y^32) / (2zy^2) not sure where to go from here      Log On


   

Question 158365: (3y^8)^4 / (2zy^2)
I started out with
(3y^32) / (2zy^2)
not sure where to go from here
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
(3y^8)^4/(2zy^2)
(3y^32)/(2zy^2) cancel out the y^2 terms.
3y^30/2z