SOLUTION: The sum of two numbers is 25. The sum of their squares are 313. Find the numbers.
My work:
x+y=25
x^2+y^2=313
x=x
y=25-x
x^2+(25-x)^2=313
x^2+625+x^2-50x=313
2x^2-50
Algebra ->
Expressions-with-variables
-> SOLUTION: The sum of two numbers is 25. The sum of their squares are 313. Find the numbers.
My work:
x+y=25
x^2+y^2=313
x=x
y=25-x
x^2+(25-x)^2=313
x^2+625+x^2-50x=313
2x^2-50
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Question 158210: The sum of two numbers is 25. The sum of their squares are 313. Find the numbers.
My work:
x+y=25
x^2+y^2=313
x=x
y=25-x
x^2+(25-x)^2=313
x^2+625+x^2-50x=313
2x^2-50x+312=0
2(x^2-25x+156)=0 Answer by jim_thompson5910(35256) (Show Source):