SOLUTION: Find the value for k that will make 4x^2+6.4x +k a perfect square.

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Question 158062: Find the value for k that will make 4x^2+6.4x +k a perfect square.
Found 2 solutions by nabla, Edwin McCravy:
Answer by nabla(475) About Me  (Show Source):
You can put this solution on YOUR website!
It is clearly evident that we will need something of the form:
(2x+a)^2=4x^2+6.4x+k
Now the x terms equated will be;
4xa=6.4x
Which gives a=1.6
So the perfect square has to be (2x+1.6)^2. Now to find k we expand and find the constant term is 2.56.


Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
Edwin's solution:
Find the value for k that will make 4x^2+6.4x +k a perfect square.
0 solutions

4x%5E2%2B6.4x+%2Bk

If it is to factor as a perfect square its 
factorizaton must be:

%282x%2Bsqrt%28k%29%29%5E2

So 

4x%5E2%2B6.4x+%2Bk+=+%282x%2Bsqrt%28k%29%29%5E2

4x%5E2%2B6.4x+%2Bk+=+%282x%2Bsqrt%28k%29%29%282x%2Bsqrt%28k%29%29



4x%5E2%2B6.4x+%2Bk+=+%282x%29%5E2%2B4x%2Asqrt%28k%29%2B%28sqrt%28k%29%29%5E2%29

4x%5E2%2B6.4x+%2Bk+=+4x%5E2%2B4x%2Asqrt%28k%29%2Bk

Since the first and last terms on each sides are equal, the
middle terms must also be equal. So we set them equal:

6.4x+=+4x%2Asqrt%28k%29

Divide both sides by x:

6.4+=+4sqrt%28k%29

Divide both sides by 4:

6.4%2F4+=+sqrt%28k%29

1.6+=+sqrt%28k%29

Square both sides:

1.6%5E2+=+%28sqrt%28k%29%29%5E2

2.56+=+k

Edwin