SOLUTION: 24. Find b^2 – 4ac and the number of real solutions for the given equation. –x^2 + 12x – 32 = 0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 24. Find b^2 – 4ac and the number of real solutions for the given equation. –x^2 + 12x – 32 = 0      Log On


   

Question 157986: 24. Find b^2 – 4ac and the number of real solutions for the given equation.
–x^2 + 12x – 32 = 0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

From -x%5E2%2B12x-32 we can see that a=-1, b=12, and c=-32


D=b%5E2-4ac Start with the discriminant formula.


D=%2812%29%5E2-4%28-1%29%28-32%29 Plug in a=-1, b=12, and c=-32


D=144-4%28-1%29%28-32%29 Square 12 to get 144


D=144-128 Multiply 4%28-1%29%28-32%29 to get %28-4%29%28-32%29=128


D=16 Subtract 128 from 144 to get 16


Since the discriminant is greater than zero, this means that there are two real solutions.