SOLUTION: Find three consecutive odd integers such that the sum of the smallest and 4 times the largest is 61.

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Question 157739: Find three consecutive odd integers such that the sum of the smallest and 4 times the largest is 61.
Found 2 solutions by checkley77, josmiceli:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
INTEGERS=X, X+2 & X+4
X+4(X+4)=61
X+4X+16=61
5X=61-16
5X=45X=45/5
X=9 ANSWER FOR THE SMALLEST INTEGER.
PROOF:
9+4(9+4)=61
9+4*13=61
9+52=61
61=61

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If I call the 1st odd integer n, then the next one
will be n+%2B+2 and the 3rd will be n+%2B+4
given:
n+%2B+4%2A%28n+%2B+4%29+=+61
n+%2B+4n+%2B+16+=+61
5n+=+45
n+=+9
n+%2B+2+=+11
n+%2B+4+=+13
The numbers are 9,11,and 13
check:
n+%2B+4%2A%28n+%2B+4%29+=+61
9+%2B+4%2A%289+%2B+4%29+=+61
9+%2B+4%2A13+=+61
9+%2B+52+=+61
61+=+61
OK