SOLUTION: Hi, can you please help, can you please help with this piecewise defined function . Piecewise defined function . f(x) = { x - 4, {{{ x <= 2 }}} } .........{ 2x + 3, {{{ 2 < x

Algebra ->  Functions -> SOLUTION: Hi, can you please help, can you please help with this piecewise defined function . Piecewise defined function . f(x) = { x - 4, {{{ x <= 2 }}} } .........{ 2x + 3, {{{ 2 < x       Log On


   



Question 157686: Hi, can you please help, can you please help with this piecewise defined function
.
Piecewise defined function
.
f(x) = { x - 4, +x+%3C=+2+ }
.........{ 2x + 3, +2+%3C+x+%3C=+14+ }
.........{ 36, +x+%3E+14+ }
.
I think the domain is ( +-+infinity+,+%2B+infinity+ )
.
I think the range is ( +-+infinity+, +-2+ ] U ( +7+, +31+ ] U { +36+ }
.
Is this domain, and range right? Can you please confirm? Please use interval notation, just like what I used for the domain and range
.
Thanks ahead of time, Levi

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = { x - 4, +x+%3C=+2+ }
.........{ 2x + 3, +2+%3C+x+%3C=+14+ }
.........{ 36, +x+%3E+14+ }
f is defined using three formulas for linear function, so graph all three of them
graph first this linear function: f%28x%29+=++x+-+4, for +x+%3C=+2+ ...........since we have a restriction +x+%3C=+2+, erase the part x%3E=2
the domain is ( +-+infinity++,+2+)

then graph this linear function: f%28x%29+=++2x+%2B+3, for +2+%3C+x+%3C=+14+ ...........since we have a restriction +2%3C=x+, erase the part from -infinity to 2 and the part where x+%3E=+14
this graph will be a line segment from x=2 to x=14
the domain is ( +2+,+14+)

then graph this linear function: f%28x%29+=+36, for +x+%3E+14+
this is constant function, so it is define for [+14+%3C+x+%3Cinfinity)
the domain is [+14+%3C+x+%3Cinfinity)