SOLUTION: a father is older than his son by 32 years.6 years ago the father was 17 times as old as his son.how old are they now?

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Question 157676: a father is older than his son by 32 years.6 years ago the father was 17 times as old as his son.how old are they now?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
a father is older than his son by 32 years.6 years ago the father was 17 times as old as his son.how old are they now?
.
Let x = son's current age
then from: "a father is older than his son by 32 years"
x+32 = father's current age
.
To derive our equation, we use "6 years ago the father was 17 times as old as his son"
(x+32)-6 = 17(x-6)
x+32-6 = 17x-102
x+26 = 17x-102
x+128 = 17x
128 = 16x
8 years = x (son's age)
.
Father's age:
x+32 = 8+32 = 40 years