SOLUTION: an airplane takes off from an airport at 7:00 A.M. traveling at a rate of 350 mi/h. two hours later, a jet takes off from the same airport following the same flight path at 490 mi/

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Question 157591This question is from textbook
: an airplane takes off from an airport at 7:00 A.M. traveling at a rate of 350 mi/h. two hours later, a jet takes off from the same airport following the same flight path at 490 mi/h. in how many hours will the jet catch up with the airplane? This question is from textbook

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let t= time 1st plane is in the air
t+-+2= time 2nd plane is in the air
When they meet, both planes will have
flown the same distance, d
d+=+350t
d+=+490%2A%28t+-+2%29
350t+=+490t+-+980
140t+=+980
t+=+7hrs
This is the time the 1st plane is in the air
The jet catches up with the 1st plane in
t+-+2hrs
7+-+2+=+5hrs answer
(actually, 2 PM)