SOLUTION: How much water should be added to 6 gallons of pure acid to obtain a 30% solution?

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Question 157217: How much water should be added to 6 gallons of pure acid to obtain a 30% solution?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
How much water should be added to 6 gallons of pure acid to obtain a 30% solution?
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Let x = amount of water added
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"amount of acid" = 30%("total volume")
6 = .30(x+6)
6 = .30x + 1.8
4.2 = .30x
14 gallons = x (this is the amount of water added)