SOLUTION: The perimeter of a rectangular garden is 24 ft. The length is 2 ft more than the width. Find the length and the width of the garden.
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-> SOLUTION: The perimeter of a rectangular garden is 24 ft. The length is 2 ft more than the width. Find the length and the width of the garden.
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Question 156964: The perimeter of a rectangular garden is 24 ft. The length is 2 ft more than the width. Find the length and the width of the garden. Found 2 solutions by midwood_trail, rogerhinson:Answer by midwood_trail(310) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangular garden is 24 ft. The length is 2 ft more than the width. Find the length and the width of the garden.
We need the perimeter of a rectangle formula: P = 2L + 2W
Let P = 24
length = x + 2
width = x
Plug into above formula and solve for x.
24 = 2(x + 2) + 2x
We need to distribute 2 across the quantity (x + 2) to remove the parentheses.
Let's do that first.
2 times x = 2x
2 times 2 = 4
This is our new equation:
24 = 2x + 4 + 2x
Combining like terms on the right side we get:
24 = 4x + 4
Subtracting 4 from both sides of the equation, we get this:
24 - 4 = 4x
20 = 4x
To find x, we use the division property of equality that tells us to divide both sides by the number next to x on both sides. So, this means we divide both sides by 4 to find the value of x.
20/4 = x
5 = x
We just found x to be 5.
However, we need to find the length and width.
Our length is x + 2
Replace x with 5 and add 2.
Length = 5 + 2
Length = 7 feet
Our width is W.
Replace W with 5.
Our width is 5 feet.
Done!
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