SOLUTION: This is a question from a worksheet - not a text book. Find the length of one side of the square when the hypotenuse is sqrt50. Thank you!

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Question 156961: This is a question from a worksheet - not a text book. Find the length of one side of the square when the hypotenuse is sqrt50. Thank you!
Found 2 solutions by rogerhinson, midwood_trail:
Answer by rogerhinson(3) About Me  (Show Source):
You can put this solution on YOUR website!
Square = Side A * Side B, Side A = Side B since it's a square
A^2 + B^2 = C^2
C = sqrt%2850%29
C^2 = 50
2(A^2) = 50
A^2 = 25
A = 5

Answer by midwood_trail(310) About Me  (Show Source):
You can put this solution on YOUR website!
This is a question from a worksheet - not a text book. Find the length of one side of the square when the hypotenuse is sqrt50. Thank you!
Let x = side of square
A square has the same length all around.
The hypotenuse is the diagonal distance in a square.
So, we now use the Pythagorean Theorem.
x^2 + x^2 = (sqrt{50])^2
On the right side, we have a square root. When we square a square root, the radical symbol vanishes. In this case, the radical symbol vanishes leaving us with 50 on the right side.
2x^2 = 50
Divide both sides by 2.
x^2 = 50/2
x^2 = 25
To find x, take the square root of both sides of the equation.
The square root of x^2 = x.
The square root of 25 is 5.
When we take the square root, there are two possible answers.
In this case, x = 5 and x = -5.
However, since we are dealing with length, REJECT -5 because distance cannot be negative.
The length of one side of this square is 5.
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