SOLUTION: Solve the problem. Tom Quig traveled 280 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major acciden
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-> SOLUTION: Solve the problem. Tom Quig traveled 280 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major acciden
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Question 156900: Solve the problem. Tom Quig traveled 280 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major accident. If the total time of travel was 8 hours, how many miles did he drive at the reduced speed? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Tom Quig traveled 280 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major accident. If the total time of travel was 8 hours, how many miles did he drive at the reduced speed?
:
Let d = no. of slow miles
then
(280-d) = no. of normal speed miles
:
Write a time equation: Time =
:
Fast time + slow time = 8 hrs + = 8
Multiply equation by 60 to get rid of the denominator; results:
(280 - d) + 6d = 60(8)
:
-d + 6d = 480 - 280
:
5d = 200
d =
d = 40 mi at 10 mph
;
:
Check solution; (280-40 = 240 mi at 60 mph)
(240/60) + (4/10) = 8; confirms our solution
