SOLUTION: A hardware store sells large nails for $5.00 per killogram and small nails for $2.00 per killogram. The owner wants to mix the nails tog et 20 kg. of a mixture that would sell for
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Question 156813: A hardware store sells large nails for $5.00 per killogram and small nails for $2.00 per killogram. The owner wants to mix the nails tog et 20 kg. of a mixture that would sell for $3.50 per killogram. How many killograms of each size does the owner need. Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! A hardware store sells large nails for $5.00 per killogram and small nails for $2.00 per killogram. The owner wants to mix the nails tog et 20 kg. of a mixture that would sell for $3.50 per killogram. How many killograms of each size does the owner need.
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Let L = weight of large nails
then, since total weight is 20 kg:
20-L = weight of small nails
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"cost of large nails" + "cost of small nails" = "cost of mixture"
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5L + 2(20-L) = 3.50(20)
5L + 40 - 2L = 70
3L = 30
L = 10 kilogram (weight of large nails)
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For small nails:
20 - L = 20 - 10 = 10 kilogram (weight of small nails)
