SOLUTION: A certain paint mixture sells for $3.40 per liter and contains white and red paint. The white paint is valued at $3.00 per liter and the red at $4.00 per liter. If 10 L of this mix
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Question 156812: A certain paint mixture sells for $3.40 per liter and contains white and red paint. The white paint is valued at $3.00 per liter and the red at $4.00 per liter. If 10 L of this mixture is needed, how much white and red must be used to make it? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! A certain paint mixture sells for $3.40 per liter and contains white and red paint. The white paint is valued at $3.00 per liter and the red at $4.00 per liter. If 10 L of this mixture is needed, how much white and red must be used to make it?
.
Let w = amount of white paint
then, since total volume is 10 L:
10-w = amount of red paint
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"cost of white paint" + "cost of red paint" = "cost of desired mixture"
.
3w + 4(10-w) = 3.40(10)
3w + 40 - 4w = 34
40 - w = 34
40 = 34 + w
6 liters = w (amount of white paint)
.
To find red paint:
10-w = 10-6 = 4 liters (amount of red paint)
