SOLUTION: If pro basktball player has a vertical leap of about 30 inches, what is his hang time? Use the hang time function V=48T^2
HIS HANG TIME IS ?? SECONDS?
Help please..
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-> SOLUTION: If pro basktball player has a vertical leap of about 30 inches, what is his hang time? Use the hang time function V=48T^2
HIS HANG TIME IS ?? SECONDS?
Help please..
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Question 156776: If pro basktball player has a vertical leap of about 30 inches, what is his hang time? Use the hang time function V=48T^2
HIS HANG TIME IS ?? SECONDS?
Help please.. Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! You were given:
V=48T^2
where
V is "vertical leap"
T is time
.
The problem gives you:
v = 30 inches
.
Simply plug it into the equation and solve for T:
V=48T^2
30=48T^2
30/48 = T^2
sqrt(30/48) = T
sqrt(0.625) = T
0.79 seconds = T
