SOLUTION: 2x-2y=15 4x+4y=10 Help, I need to solve for x and y

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Question 156745: 2x-2y=15
4x+4y=10
Help, I need to solve for x and y

Found 2 solutions by Earlsdon, Electrified_Levi:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x and y"
1) 2x-2y+=+15
2) 4x%2B4y+=+10 First, multiply equation 1) by 2 to get:
1a) 4x-4y+=+30 now add this to equation 2) to eliminate the y's
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8x+=+40 Divide both sides by 8.
x+=+40%2F8
x+=+5 Now substitute this value of x into either equation 1) or eqation 2) to find y. Let's use equation 1)
1) 2x-2y+=+15 Substitute x = 5.
2%285%29-2y+=+15 Simplify.
10-2y+=+15 Subtract 10 from both sides.
-2y+=+5 Divide both sides by -2.
y+=+-5%2F2
The solution is: (5, -5/2)

Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help,
.
2x-2y=15
4x+4y=10
Help, I need to solve for x and y
.
First, you can reduce the second equation, by multiplying each side by "2"
.
4x%2B4y=10 = %284x%2B4y%29%2F2=10%2F2 = %284x%2B4y%29%2F2=10%2F2 = %284x%29%2F2%2B%284y%29%2F2=10%2F2 = 2x%2B2y=5
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The second equation +4x%2B4y=10+ is reduced to +2x%2B2y=5+
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The Two equations are
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+2x-2y=15+
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+2x%2B2y=5+
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This is the way I usually solve these equations, First, solve for a letter(usually the easiest letter), we will solve for "x" in both equations
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Equation 1 = +2x-2y=15+
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Now we will move (-2y) to the right side
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+2x-2y=15+ = +2x-2y+%2B+2y=15+%2B+2y+ = +2x+=+15+%2B+2y+
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We will rearrange the numbers
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+2x+=+15+%2B+2y+ = +2x+=+2y+%2B+15+
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We will divide each side by "2" to get "x"
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+2x%2F2+=+%282y+%2B+15%29%2F2+ = +x+=+%282y+%2B+15%29%2F2+
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Our first "x" = +%282y+%2B+15%29%2F2+
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Now let's solve "x" in our second equation, +2x%2B2y=5+
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We will move (2y) to the right side
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+2x%2B2y=5+ = +2x%2B2y+-+2y=5+-2y+ = +2x=+5+-2y+
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We will rearrange the numbers
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+2x=+5+-2y+ = +2x=+%28-2y%29+%2B+5+
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We will divide each side by "2" to get "x"
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+2x=+%28-2y%29+%2B+5+ = +2x%2F2=+%28%28-2y%29+%2B+5%29%2F2+ = +x=+%28%28-2y%29+%2B+5%29%2F2+
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Our second "x" = +%28%28-2y%29+%2B+5%29%2F2+
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Since "x" is one number, and "x" equals our two answers, our answers equal each other, we can put our two answers in an equation
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Answer 1 = +%282y+%2B+15%29%2F2+
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Answer 2 = +%28%28-2y%29+%2B+5%29%2F2+
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+%282y%2B15%29%2F2+=+%28%28-2y%29+%2B+5%29%2F2+
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We will now solve for "y"
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+%282y%2B15%29%2F2+=+%28%28-2y%29+%2B+5%29%2F2+
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We will use cross multiplication
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+highlight%282y%2B15%29%2F2+=+%28%28-2y%29+%2B+5%29%2Fhighlight%282%29+ = +%282y%2B15%29%2Fhighlight%282%29+=+highlight%28%28-2y%29+%2B+5%29%2F2+
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It will become +%282y%2B15%29%282%29+=+%282%29%28%28-2y%29%2B5%29+
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We will rearrange numbers
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+%282y%2B15%29%282%29+=+%282%29%28%28-2y%29%2B5%29+ = +%282%29%282y%2B15%29+=+%282%29%28%28-2y%29%2B5%29+
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We will use the distribution method
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=
.
=
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+4y+%2B+30+=+%28-4y%29+%2B+10+
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Now we will solve for "y", we will move (-4y) to the left
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+4y+%2B+30+=+%28-4y%29+%2B+10+ = +4y+%2B+4y+%2B+30+=+%28-4y%29+%2B+4y+%2B+10+ = +8y+%2B+30+=+10+
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Now we will move (30) to the right side
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+8y+%2B+30+=+10+ = +8y+%2B+30+-30+=+10+-30+ = +8y+=+%28-20%29+
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Now to find "y" we will divide each side by "8"
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+8y+=+%28-20%29+ = +8y%2F8+=+%28-20%29%2F8+ = +y+=+%28-20%29%2F8+, if we reduce +y+=+%28-5%29%2F2+
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y = +%28-5%29%2F2+
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To find "x" all you do is substitute "y" with +%28-5%29%2F2+ in one of our original equations
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+2x-2y=15+
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+2x%2B2y=5+
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Let's use the second equation(replace "y" with +%28-5%29%2F2+ )
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+2x%2B2y=5+ = +2x%2B2%28%28-5%29%2F2%29=5+ = +2x%2B%28-5%29=5+ = +2x-5+=5+
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We will move (-5) over to the right side
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+2x-5+=5+ = +2x-5+%2B+5+=5+%2B+5+ = +2x+=10+
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Now we will divide each side by "2" to get "x"
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+2x%2F2+=10%2F2+ = +x+=10%2F2+ = +x+=5+
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x = +5+
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We can check our answers by replacing "x" and "y" with our answers we got, in our very first equations
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x = +5+
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y = +%28-5%29%2F2+
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Let's replace "x" and "y" with the numbers above
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+2x-2y=15+ = +2%285%29-2%28%28-5%29%2F2%29%29=15+ = +10+-%28-5%29=15+ = +10+%2B5+=15+ = +15+=15+ (True)
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+4x%2B4y=10+ = +4%285%29%2B4%28%28-5%29%2F2%29=10+ = +20%2B%28-10%29=10+ = +20-10=10+ = +10=10+ (True)
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This method will work for all problems like this
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x = +5+
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y = +%28-5%29%2F2+
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The ordered pair is (x,y), our ordered pair is (5, +%28-5%29%2F2+ )
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Hope I helped, Levi