Question 156697This question is from textbook Beginning and Intermediate Algebra
: I hope I picked the right topic...
Here is the word problem, out of my book:
In the 2005 regular baseball season, the Chicago White sox won 27 fewer than twice as many games as they lost. They played 162 regular-season games. How many wins and losses did the team have?
I have been trying to figure this problem out with my friend for the last two days. We are stuck on it. I finally thought that I figured it out today, and seeing as it has been such a burden to us, I decided to look up the figures online and found out that I was wrong! So now I know what the correct answer is, but I want to know how to reach it. Here is what I had done when I thought I finally figured it out:
2x-27=62
2x=189
x=94.5
I questioned myself when a fraction came up, but seeing as it is a half, I figured maybe they tied one game with another team??
From there, I went on to do this:
162-94.5=67.5
So I figured that 67.5 and 94.5 were my answers. When I added them together to check my math, I found that they do add up to 162. I don't know anything about baseball so I don't know if tying is even possible... I guess it isn't, since my answer is wrong.
Some help in understanding how the correct answer of 99 wins and 63 losses is reached would be wonderful.
Thank you very much.
This question is from textbook Beginning and Intermediate Algebra
Found 2 solutions by nerdybill, jim_thompson5910:
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website!
In the 2005 regular baseball season, the Chicago White sox won 27 fewer than twice as many games as they lost. They played 162 regular-season games. How many wins and losses did the team have?
.
Let x = games lost
which means (because they played a total of 162 games) that
162 - x = games won
.
2x-27 = 162 - x
3x-27 = 162
3x = 189
x = 63 (games lost)
.
162 - 63 = 99 (games won)
Answer by jim_thompson5910(35256)  (Show Source):
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