SOLUTION: 1.x^4=5x^2 2.x^4+18x^3+8x+144=0 3.x^3+19x^2-7x-133=0 4.x^6-13x^5-7x=-91 I need help solving these. So far I have spent hours on just these problems our teacher doesn't explain

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 1.x^4=5x^2 2.x^4+18x^3+8x+144=0 3.x^3+19x^2-7x-133=0 4.x^6-13x^5-7x=-91 I need help solving these. So far I have spent hours on just these problems our teacher doesn't explain       Log On


   



Question 156591: 1.x^4=5x^2
2.x^4+18x^3+8x+144=0
3.x^3+19x^2-7x-133=0
4.x^6-13x^5-7x=-91
I need help solving these. So far I have spent hours on just these problems our teacher doesn't explain things very well.
Thanks
Lauren

Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1.x^4=5x^2
x^4 - 5x^2 =
x^2 (x^2 - 5) = 0
x^2 (x-sqrt(5))(x+sqrt(5)) = 0
x = 0 or x = sqrt(5) or x = -sqrt(5)
---------------------------------
2.x^4+18x^3+8x+144=0
x^3(x+18) + 8(x+18) = 0
(x+18)(x^3+8) = 0
(x+18)(x+2)(x^2-2x+4) = 0
x = -18 or x = -2 or x^2-2x+4 =0
---
Use the quadratic formula on x^2-2x+4
x = [2 +- sqrt(4 - 4*1*4)]/2
x = [2 +- sqrt(-12)]/2
x = [1 +- isqrt(3)]
----------------------------------
3.x^3+19x^2-7x-133=0
x^2(x + 19) -7(x+19) = 0
(x+19)(x^2-7) = 0
(x+19)(x-sqrt(7))(x+sqrt(7)) = 0
x = -19 or x=sqrt(7) or x=-sqrt(7)
----------------------------------
4.x^6-13x^5-7x=-91
x^6 - 13x^5 -7x + 91 = 0
x^5(x-13) - 7(x-13) = 0
(x-13)(x^5-7) = 0
x = 13 and x = 7^(1/5)
=============================
Cheers,
Stan H.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
1) x%5E4+=+5x%5E2 Divide both sides by x%5E2
x%5E4-5x%5E2+=+0 Factor out an x%5E2
x%5E2%28x%5E2-5%29+=+0 Apply the zero product rule: If a*b = 0, then either a = 0 or b = 0 or both.
x%5E2+=+0 or x%5E2-5+=+0
If x%5E2+=+0 then x+=+0 and x+=+0
If x%5E2-5+=+0 then x%5E2+=+5 Take the square root of both sides to get:
x+=+sqrt%285%29 or x+=+-sqrt%285%29
Now because this is a fourth degree polynomial, you can expect four solutions, some of which may be identical.
The solutions are:
x+=+0
x+=+0
x+=+sqrt%285%29
x+=+-sqrt%285%29
--------------------------------
2) x%5E4%2B18x%5E3%2B8x%2B144+=+0 This polynomial can be factored into:
%28x%5E3%2B8%29%28x%2B18%29+=+0 and the first factor can be further factored as it is the sum of two cubes %28x%29%5E3 and 2%5E3, so we get:
%28x%2B2%29%28x%5E2-2x%2B4%29%28x%2B18%29+=+0 Now, applying the zero product rule that was used in the first problem, you will set each of these three factors equal to zero.
x%2B2+=+0 Here, x+=+-2
x%5E2-2x%2B4+=+0 Here, we'll have to use the quadratic formula to solve for x: x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a and a = 1, b = -2, and c = 4, so...
x+=+%28-%28-2%29%2B-sqrt%28%28-2%29%5E2-4%281%29%284%29%29%29%2F2%281%29 Simplifying this, we get:
x+=+%282%2B-sqrt%284-16%29%29%2F2
x+=+%282%2B-sqrt%28-12%29%29%2F2
x+=+%282%2B-sqrt%284%28-3%29%29%29%2F2
x+=+%282%2B2%2Asqrt%28-3%29%29%2F2 or x+=+%282-2%2Asqrt%28-3%29%29%2F2 Simplifying this:
x+=+1%2Bsqrt%283%29i or x+=+1-sqrt%283%29i
...and for the last one:
x+%2B+18+=+0
x+=+-18
So, as in the first problem, because you have a fourth degree polynomial, you can expect four solutions, and they are:
x+=+-2
x+=+1%2Bsqrt%283%29i
x+=+1-sqrt%283%29i
x+=+-18
-----------------
3) x%5E3%2B19x%5E2-7x-133+=+0 You can solve this by "factoring by grouping"
%28x%5E3%2B19x%29-%287x%2B133%29+=+0 Now factor each of the two terms:
x%5E2%28x%2B19%29-7%28x%2B19%29+=+0 Factor out the common factor of x%2B19
%28x%2B19%29%28x%5E2-7%29+=+0 Apply the zero product rule.
x%2B19+=+0 or x%5E2-7+=+0 so...
x+=+-19 or x%5E2+=+7
x%5E2+=+7 Take the square root of both sides.
x+=+sqrt%287%29 or x+=+-sqrt%287%29
The three solutions are:
x+=+-19
x+=+sqrt%287%29
x+=+-sqrt%287%29
----------------
I'll get you started on the last one but see if you can finish it up yourself.
4) x%5E6-13x%5E5-7x+=+-91 Add 91 to both sides.
x%5E6-13x%5E5-7x-91+=+0 Factor by grouping.
%28x%5E6-13x%5E5%29-%287x-91%29+=+0 Factor an x%5E5 from the first term and a 7 from the second term.
x%5E5%28x-13%29-7%28x-13%29+=+0 Now factor the common factor %28x-13%29
%28x-13%29%28x%5E5-7%29+=+0 Apply the zero product rule.
x-13+=+0 or x%5E5-7+=+0
Can you finish this?