SOLUTION: The height h, in feet of a baseball above the ground t seconds after it is hit, is given by h= -16t^2 + 50t +4.5
Use this equation to determine the number of seconds, to the ne
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: The height h, in feet of a baseball above the ground t seconds after it is hit, is given by h= -16t^2 + 50t +4.5
Use this equation to determine the number of seconds, to the ne
Log On
Question 156573This question is from textbook
: The height h, in feet of a baseball above the ground t seconds after it is hit, is given by h= -16t^2 + 50t +4.5
Use this equation to determine the number of seconds, to the nearest tenth of a second, from the time the ball is hit until the ball hits the ground.
Show all of your algebra work. This question is from textbook
You can put this solution on YOUR website! h = -16t^2 + 50t + 4.5
when the ball hits the ground, h will be 0
so solve the equation
-16t^2 + 50t + 4.5 = 0
solve using quadratic equation (-b +/- sqrt(b^2-4ac))/2a.
a = -16
b = 50
c = 4.5
use calculator and do not round until the end.
b^2 = 2500
4ac = 4*(-16)*4.5 = (-288)
b^2-4ac = 2500 - (-288) = 2788
sqrt(b^2-4ac) = 52.80151513
formula then becomes (-50 +/- 52.80151513) / -32
t = 3.212547345 or t = .087547348
substituting in original equation for t = 3.212547345
(-16 * 10.32046046) + (50 * 3.212547345) + 4.5 = something very close to 0.
substituting in original equation for t = .087547345
(-16 * .007) + (50 * .087) + 4.5 = something very positive so this is not the answer.
answer is t = 3.2 seconds rounded to the nearest tenth of a second.
(