Question 156490: Karen is in the center of a circular track of radius 90 feet watching Abigail and Mercury run a race. When Abigail wins, Karen notices that the angle formed by drawing a line from the center of the track to Abigail and a line from the center of the track to Mercury measures 4 radians. How far, in feet, behind Abigail is Mercury when Abigail wins?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Karen is in the center of a circular track of radius 90 feet watching Abigail and Mercury run a race. When Abigail wins, Karen notices that the angle formed by drawing a line from the center of the track to Abigail and a line from the center of the track to Mercury measures 4 radians. How far, in feet, behind Abigail is Mercury when Abigail wins?
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The perimeter of the track is (pi)d = 180pi feet
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Angular difference in position = 4 radians
Linear difference in position = (4/(2pi))*(180pi ft.) = 360 ft.
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Cheers,
Stan H.
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